(1/a)=(-6)/(a^2+5)

Solution for (1/a)=(-6)/(a^2+5) equation:

D( a )

a = 0

a^2+5 = 0

a = 0

a = 0

a^2+5 = 0

a^2+5 = 0

1*a^2 = -5 // : 1

a^2 = -5

a in (-oo:0) U (0:+oo)

1/a = -6/(a^2+5) // + -6/(a^2+5)

1/a-(-6/(a^2+5)) = 0

6*(a^2+5)^-1+1/a = 0

6/(a^2+5)+1/a = 0

(6*a)/(a*(a^2+5))+(1*(a^2+5))/(a*(a^2+5)) = 0

1*(a^2+5)+6*a = 0

a^2+6*a+5 = 0

a^2+6*a+5 = 0

a^2+6*a+5 = 0

DELTA = 6^2-(1*4*5)

DELTA = 16

DELTA > 0

a = (16^(1/2)-6)/(1*2) or a = (-16^(1/2)-6)/(1*2)

a = -1 or a = -5

(a+5)*(a+1) = 0

((a+5)*(a+1))/(a*(a^2+5)) = 0

((a+5)*(a+1))/(a*(a^2+5)) = 0 // * a*(a^2+5)

(a+5)*(a+1) = 0

( a+1 )

a+1 = 0 // - 1

a = -1

( a+5 )

a+5 = 0 // - 5

a = -5

a in { -1, -5 }